(2Z+6)^2=-16

Question

We have to solve it over the complex field and have it in a+bi form

Answer 1

(2z+6)²=-16

2z+6=√-16

2z+6=4√-1

2z+6=4i

2z=-6+4i

z=-3+2i

-(2z+6)=√-16

-2z-6=4i

-2z=6+4i

z=-3-2i