Great question. First, we must break the two scenarios down and find the force of impact for both.
For this, let's say
Your weight is 100lbs
The height of the drop 10ft
g = 9.8m/2
10 ft = 3.048 m
100lbs = 45.36kg
For Seaniro 1: Straight Down
v = √(2gh)
v = √(2 * 9.8 * 3.048)
v = 7.71 m/s
F = mv/t
F = (45.36 * 7.71) / 0.05
F = 6,996N
Scenario 2: Tipping over
w = √(3g)/L
w = √(3 * 9.8) / 1.8
w = 4.04 rad/s
v = w * L
v = 4.04 * 1.8
v = 7.27 m/s
F = mv/t
F = (45.36 * 7.27) / 0.02
F = 16,490N
Now, the actual force of impact from tipping over is greater than that of falling straight down. Since, assumingly if you hold on to the ladder while it tips, you will land on your side. So the force of impact will be felt over a larger surface area of your body. Whereas, falling straight down, you will land on your feet, thus, more force is felt in a smaller area.
While both are survivable, both are very dangerous. The risk of injury of fractures, internal organ damage, and broken bones is high with both. Please note that in the tipping-over scenario, this is slightly more dangerous as the risk of hitting your head is greater.