Francisco P. answered 11/18/14
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Rigorous Physics Tutoring
The wave speed is given by v = √(T/μ) where T is the tension and μ = m/L is the mass per unit length.
v = √(125/(0.007/2.00)) = 189 m/s
Integer half-wavelengths have to fit within the length of the string, L = 2.00 m, because the ends are clamped.
L = n(λn/2) or λn = 2L/n for n = 1, 2, 3, ...
The frequency is related to the wavelength through v = λnfn.
Using the result above, the possible frequencies are fn = (n/2L)v.
For n = 1:
λ1 = 2L/1 = 4.00 m
f1 = (1/2L)(189) = 47.25 Hz