acceleration parallel to the bannister = g sin(30°) = 4.905 ms-2
Using Kinematic equations , The final velocity is calculated as
Vf2 = Vi2 + 2*a*S
Vf = 98.1 ms-1
Emma L.
asked 03/16/19The bannister's is inclined at 30 degree. Determine the exit velocity from a 10 m long bannister which is frictionless.
acceleration parallel to the bannister = g sin(30°) = 4.905 ms-2
Using Kinematic equations , The final velocity is calculated as
Vf2 = Vi2 + 2*a*S
Vf = 98.1 ms-1
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