How do you solve eln(1−x)=2xeln⁡(1−x)=2x?

Answer 1

Then x = 1/2, since e * ln(1-x) cancels from the first two equations.

We have e* ln(1-x) = 1

ln(1-x) = 1/e

1-x = e^(1/e)

x = 1 - e^(1/e)