A parcel of land is 9 ft longer than it is wide. Each diagonal from one corner to the opposite corner is 261 ft long. What are the dimensions of the parcel?

Answer 1

x^2 + (x+9)^2 = 261^2

x^2 + x^2 + 18x + 81 = 261^2

2x^2 + 18x - 68040 = 0

x^2 + 9x - 34020 = 0

(x - 180 )( x + 189 ) = 0

x+189 = 0 results in negative measures

x -180 = 0 ---> x =180

180 by 189