Yanal K. answered • 11/16/14

Tutor

New to Wyzant
Energetic & Fun University Student for Mathematics

Hello Mary,

The two numbers are:

692 + 437 or 697 + 432

There really isn't a way to do this other than trial and error from what I know, but there are a couple of tips.

There are only a couple tips to keep in mind. From the digits we are given: 6, 9, 2, 4, 3, and 7, we need to see what numbers make sense as the beginning and end because once we know those, the middle won't matter.

We know the first two digits must not add to greater than 11 of 1129 and the last two must add to 9 to equal the ending digit of 1129.

The end numbers, once added, must equal 9 and the only two combinations are 7 and 2 or 6 and 3.

Let's try 6 & 3 first. The numbers must then be:

--6

--3

From this, we have left 2, 4, 7, and 9. 9 and 7 can't be the first two numbers, but it can be 7 and 4 or 7 and 2 so let's try 7 and 4.

796 + 243 = 1039 which is too small. Now, we know that 7 and 2 will be even smaller and 9 and 4 is already too big to be the first two numbers because it will be 13, already over 11 of 1129. Hence, we know the last two digits are 2 and 7 because 3 and 6 don't work.

The numbers must then be:

--7

--2

with 4, 3, 6, and 9 left. From this, we now need to see what two numbers get us to 1129. We know 9 can't be the first digit because all additions are greater than 11. Let's try 6 and 3 as the first two digits. We get:

697 + 342 = 1039 which is too small meaning 4 and 3 is also too small. Now, we try the next larger number by switching the 3 and 4 to get:

697 +432. This gives us : 1129.

I hope this helped. :)

Mary C.

11/16/14