Lets see by replacing x with (-x)
(-x)^3*(sin(-x))4
=-x3(-sinx)4
=-x3(-1*sinx)4
=-x3(-1)4*(sinx)4
=-x3*1*(sinx)4
=-x3(sinx)4
=-x3(sin4x)
-[x3(sin4x)]
-(original expression) which means the original expression is odd
Lets see by replacing x with (-x)
(-x)^3*(sin(-x))4
=-x3(-sinx)4
=-x3(-1*sinx)4
=-x3(-1)4*(sinx)4
=-x3*1*(sinx)4
=-x3(sinx)4
=-x3(sin4x)
-[x3(sin4x)]
-(original expression) which means the original expression is odd
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