If I an understanding the question correctly, then the jet is flying 33 degrees from the North in the eastern direction. Flying 8 miles, and then 90 degrees to its right for 11 miles would form a right triangle whose legs are 8 and 11. So its hypotenuse would be sqrt(8^2+11^2) = sqrt(185). Using the definition of tangent being tan x (if x=angle adjacent to the first leg & opposite to its second leg), tan x = opp/hyp = 11/8 = 1.375. So arctan (1.375) = 53.97 degrees. Adding this 53.97 to the 33 degrees bearing from North,(and rounded to the nearest tenth degree) = 54.0+33 = 87.0 degrees bearing from the control tower.
