Philip P. answered 11/12/14
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x+8 (x+8)
----------- = --------------
(x2-64) (x+8)(x-8)
We can't have the denominator = 0, which happens when x = 8 or x= -8. Hence the expression is not defined at these values. The expression simplifies to 1/(x-8), but it is still undefined at both x = 8 and x = -8.
x2-4x-32 (x-8)(x+4)
------------- = ---------------
x2-4x-12 (x-6)(x+4)
Again, the denominator equals zero when x = 6 or -4,, so the expression is not defined at these values of x. The expression simplifies to (x-8)/(x-6), but it is still undefined at both x = 6 and x = -4.