Kevin C. answered • 11/10/14

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If the two nun=mbers are x and x+1, the reciprocals of these are 1/x and 1/(x+1)

Therefore the equation is 1/x + 1/(x + 1) = 9/20.

Multiply this equation by the Least Common denominator 20(x)(x+1).

This becomes 20(x)(x+1)/x + 20(x)(x+1)/(x+1) = 9(20)(x)(x+1)/20

Simplifying: 20(x+1) + 20(x) = 9(x)(x+1)

And we get 20x + 20 + 20x = 9x

^{2}+ 9x.Set equal to 0: 9x

^{2}-31x - 20 = 0Factor: (9x - 5)(x - 4) = 0. Solve for the integer x.

I hope this helps.