cos(a-b)=cos(a)cos(b) + sin(a)sin(b)
So what you have is
Cos[(5π/12)-(π/4)]
Common denominator would be 12 multiply the top and bottom of π/4 by 3
Cos[(5π/12)-(3π/12)]
Cos(2π/12)
Cos(π/6)=√3/2=0.866
Millburn H.
asked 03/12/19cos(a-b)=cos(a)cos(b) + sin(a)sin(b)
So what you have is
Cos[(5π/12)-(π/4)]
Common denominator would be 12 multiply the top and bottom of π/4 by 3
Cos[(5π/12)-(3π/12)]
Cos(2π/12)
Cos(π/6)=√3/2=0.866
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.