Denise G. answered 07/29/19
Algebra, College Algebra, Prealgebra, Precalculus, GED, ASVAB Tutor
(1) The max height would be 38-30 = 8 ft off the ground
(2) It wouldn't be as good of a ride if you went negative, into the ground.
(3) A =15 is the amplitude, it is 1/2 of the diameter of the ferris wheel.
2π/B = time for one revolution, solving for B = π/10
C=5
D = 8 +15 = 23
y=15 sin π/10(t-5)+23
(4) Plugging in values into the equation
at t=3, y=14.2 ft
at t=15, y=23 ft
at t=19, y=8.7 ft
Diane B.
If the rider starts a quarter of the way around the ferris wheel at t=0, don't you need to factor that position in to all of the answers in step 4 of the problem? It looks like the answers provided in step 4 assume the rider began the ride at t=0 at the bottom of the ferris wheel.07/29/20