
Patrick B. answered 06/04/19
Math and computer tutor/teacher
E = M-6
P = E/2 = (M-6)/2
E+P+M = 76
(M-6) + (M-6)/2 + M = 76
2(M-6) + (M-6) + 2m = 152
2m-12 + m-6 + 2m = 152
5m - 18 = 152
5m = 170
m = 34
34 math
28 english
14 philosophy
Estuardo U.
asked 03/01/19At Edmonds Community College freshman need to take a 100 level Math and English plus optional Philosophy course.
In any quarter the college needs to make available 6 less English sections than Math sections.
In any quarter student demand for the optional Philosophy course is half as many sections as English sections.
Available classrooms limit the total sections of all three courses to 76
Given these constraints how many sections of each course should the college make available each quarter to meet demand?
Patrick B. answered 06/04/19
Math and computer tutor/teacher
E = M-6
P = E/2 = (M-6)/2
E+P+M = 76
(M-6) + (M-6)/2 + M = 76
2(M-6) + (M-6) + 2m = 152
2m-12 + m-6 + 2m = 152
5m - 18 = 152
5m = 170
m = 34
34 math
28 english
14 philosophy
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