sin(A-B))/cosAcosB = (sinAcosB - cosAsinB)) / cosAcosB =
sinAcosB/cosAcosb - cosAsinB/cosAcosB = sinA/cosA - sinBcosB = tanA - TanB
Summer B.
asked 02/27/19Establish The identity is true by transforming one side to the other side. Be sure to show all steps and to put each step below previous step.
sin(A-B))/cosAcosB = (sinAcosB - cosAsinB)) / cosAcosB =
sinAcosB/cosAcosb - cosAsinB/cosAcosB = sinA/cosA - sinBcosB = tanA - TanB
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