
Jon S. answered 03/18/19
Patient and Knowledgeable Math and English Tutor
sin(A-B))/cosAcosB = (sinAcosB - cosAsinB)) / cosAcosB =
sinAcosB/cosAcosb - cosAsinB/cosAcosB = sinA/cosA - sinBcosB = tanA - TanB
Summer B.
asked 02/27/19Establish The identity is true by transforming one side to the other side. Be sure to show all steps and to put each step below previous step.
Jon S. answered 03/18/19
Patient and Knowledgeable Math and English Tutor
sin(A-B))/cosAcosB = (sinAcosB - cosAsinB)) / cosAcosB =
sinAcosB/cosAcosb - cosAsinB/cosAcosB = sinA/cosA - sinBcosB = tanA - TanB
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