if two roots of a quadratic equation ax^2 bx c=0 differs 1 prove that b^2 - 4ac = a^2

Question

please help fast asap rocky need answer fast help

Answer 1

let Δ = b² - 4ac

let r+1 = (-b + √Δ)/2a

and r = (-b-√Δ)/2a

Subtract the 2nd equation from the first

1 = (√Δ)/a and Δ = a²

Q.E.D.