How much work is required to move a 100 kg object up a smooth board 5.00 m long if one end of the board is placed in a windowsill 1.50m above the ground?

Answer 1

The work required to push the weight up the board is the same as if you lifted the weight straight up to the

1.5 meter height (Assuming no friction!). You just use less force to push it up the incline but you push it a longer distance.

In either case, the Work = Force*Distance = (Weight)*(Height)=(100 kg)(9.8m/s²)(1.5m) = 1,470 (kg-m²)/sec²

or Work = 1,470 N-m