If 5 J of work is needed to stretch a spring 10 cm beyond the equilibrium, how much work, W, is required to stretch it 16 cm beyond the equilibrium?

Answer 1

(1) Use the Work-Energy theorem of delta(E) = W => 1/2 k x² = Work Done.

(2) Solve for k (spring constant) using the initial values.

(3) Plug in for k to delta(E)=W with new values.

(4) Solve for W.