Inactive Tutor answered 02/16/19
You can use one of the kinematic equations of motion to solve this problem. Those equations are:
Δx = xf - xi
vavg = ½ (vf + vi) = Δx / Δt
vf = vi + at
xf = xi + vit + ½ at2
vf2 = vi2 + 2a(xf − xi)
In this case, since we are looking for velocity and we have the initial velocity (0, since the car was initially at rest) and we have the time (54 sec), and we have the acceleration (3 m/s2), we would use the third equation vf = vi + at
vf = 0 + (3)(54) = 162 m/s