Let S1 = speed of first car and S2 = speed of the second car = S1 + 15
Then S1(3) + S2(3) = 375 = 3S1 + 3(S1 + 15) = 3S1 + 3S1 + 45 = 6S1 + 45 = 375
Therefore, S1 = 55 mph S2 = S1 + 15 = 70 mph
DB L.
asked 02/13/19Two cars leave town at the same time and travel in opposite directions. The average rate of speed of one car is 15 miles per hour faster than the average rate of speed of the other car. The cars are 375 miles apart after three hours. Find the average rate of speed of the two cars.
Let S1 = speed of first car and S2 = speed of the second car = S1 + 15
Then S1(3) + S2(3) = 375 = 3S1 + 3(S1 + 15) = 3S1 + 3S1 + 45 = 6S1 + 45 = 375
Therefore, S1 = 55 mph S2 = S1 + 15 = 70 mph
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