The length of a rectangle is 7 yd. more than 2 times the width. If the perimeter of the rectangle is 44 yd., find the length and the width.

Question

The length of a rectangle is 7 yd. more than 2 times the width. If the perimeter of the rectangle is 44 yd., find the length and the width.



Answer 1

L=2W + 7 Length is 7 more than 2 times width.

Perimeter is 2L + 2W.

Let's plug in 2W+7 (from the first equation) for L in the second equation.

2(2W + 7) + 2W = 44

Distribute the 2: 4W + 14 + 2W = 44

Combine like terms: 6W + 14 = 44

Subtract 14 from both sides: 6W = 30

Divide both sides by 6: W = 5

Now we can plug 6 in for W in either equation to solve for L.

2W + 2L = 44

2(6) + 2L = 44

12 + 2L = 44

2L = 32

L = 16