in algebra how would you Write the equation of the line that passes through (-4, 3) and (1, 13).

Question

in algebra how would you Write the equation of the line that passes through (-4, 3) and (1, 13).

Answer 1

You would first find the slope of the line:

 

m = y₁ - y₂  =  3 - 13 

       x₁ - x₂        -4 - 1

 

m = -10/-5 = 10/5 = 2

 

Then you would so the point slope form:

 

y - y₁ = m(x - x₁)

y - 3 = 2(x - (-4))

 

If you want to solve for y to get the y intercept form:

 

y - 3 = 2(x + 4)

y - 3 = 2x + 8

y = 2x + 11

Answer 2

I'll write the equation in the form

y = mx + b

Where m is the slope and b is the y intercept

 

 

m = (13 - 3) / (1 - (-4)) = 10 / 5 = 2

 

To find b, We plug in one of the points in the equation

 

y = 2x + b.

 

3 = 2(-4) + b

b = 11

 

Equation of the line is

y = 2x + 11