what is 2x-3(x-2y)+1/2(6x-8y) in standard form

Answer 1

First you need to distribute the -3(x-2y). That gives you -3x+6y.

Then distribute 1/2(6x-8y). That gives you 3x-4y.

So now you have 2x-3x+6y+3x-4y.

Now combine like terms (put x with x and y with y). 2x-3x+3x = 2x. 6y-4y= 2y

Your answer is 2x+2y

Answer 2

Hi Lily...the problem wants you to follow order of operations and distribute the value outside of the parentheses and then combine all like terms... for example 3(x + 2y) = 3x + 6y