Center (6,-5) passing through point (1,7)

Question

Center (6,-5) passing through point (1,7)

Answer 1

Equation of circle with center (h,k) and radius r: (x-h)² + (y-k)² = r²

So, (x-6)² + (y+5)² = r²

Since (1,7) is on the circle, (1-6)² + (7+5)² = r²

Solving for r, we get r = 13

Equation of circle: (x-6)² + (y+5)² = 169