Arthur D. answered 10/30/14
Tutor
4.9
(125)
Forty Year Educator: Classroom, Summer School, Substitute, Tutor
√(4/16*2)√(a3/a-3)√(b-6/b)√(x2/x-4)
√(1/8)√(a6)√(b-7)√(x6)
(1/2)√(1/2)(a3)(b-3)√(b-1)(x3)
(a3x3/2b3)√(1/2b)
√(1/2b)=1/√(2b)=√(2b)/2b
(a3x3/2b3)(√(2b)/2b becomes...
a3x3√(2b)/4b4