Use partial fractions to do this.
1/(x+x3) = (1/x) - [x/(1+x2)]
The integral then is ln x - (1/2)ln(1+x2) which you can simply (and, of course, add the constant of integration).
Astha S.
asked 01/03/19
Use partial fractions to do this.
1/(x+x3) = (1/x) - [x/(1+x2)]
The integral then is ln x - (1/2)ln(1+x2) which you can simply (and, of course, add the constant of integration).
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