Work = Force x Distance
For a spring F = kx, so 120 = k·(0.06). Solving for k we get k = 2000. Note that I converted 6 cm to 0.06 m so everything was in SI units. To stretch the spring another 6 cm means a total of 12 cm or 0.12 m. The work done is:
Work = Force x Distance
Work = kx·x = kx2
Work = 2000·(0.12)2 = ____? The units are joules.