A cylindrical tank of radius 4 ft and length 12 ft is lying on its side on horizontal ground. The tank initially is full of gasoline weighing 40 lb/ft3. How much work is done in pumping all this gasoline to a point 6 ft above the top of the tank?
The volume of the tank will be:
∏r2X12 ft3 = 603.20 ft3
Work is the act of changing the energy of a particle, body or system, in our case is force times space so the total weight is
40X603.20 = 24128 lb
The space will be 6 ft
and the work is
24128 X 6 = 144768 ft-lbf =