Find the zeros of f

Question

f(x) = −x^2e^−x + 2xe^−x

 

x=?

Answer 1

f(x) = -x²e^-x + 2xe^-x = 0

Since e^-x ≠ 0, divided both sides by e^-x.

-x² + 2x = 0

x(-x + 2) = 0

x = 0 or 2