Ishwar S. answered  12/16/18
University Professor - General and Organic Chemistry
CaCO3 → Ca2+ + CO32-
As you can see from the above reaction, 1 mole of CaCO3 contains 1 mole of Ca2+ ions.
Use stoichiometry to convert 1000 mg of CaCO3 to moles of Ca2+ ions. However, we need to first convert the mass in mg to g before starting the stoichiometry calculations.
1000 mg x (1 g / 1000 mg) = 1 g
1 g CaCO3 x (1 mol CaCO3 / 100.09 g CaCO3) x (1 mol Ca2+ / 1 mol CaCO3) = 0.01 mol Ca2+ (rounded to 1 significant figure)
 
    