What is the value of h?

Question

The vertex of the parabola y=(x-b)^2+b+h has coordinates (2,5). What is the value of h?

Answer 1

I will not solve this for you, but I will tell you how to solve it.

First, expand the binomial to get x² - 2bx + b² + h

The vertex occur as x = -B/2A = (2b/2) = 2, i.e. b = 1

Now plug b into the expanded equation and substitute 2 for x.

The value of the equation which will contain h as a variable = 5.