log y = log 4 + x log 1.4 ---- now do you get it?
Andi T.
asked 11/28/18Please help! I've been trying to solve this for so long. If the equation is y=4(1.4)^x is plotted on a semilog scale graph, then the linearized equation will be log(y)=mx+b where m = ? and b = ?
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