sin(A-B) = sinAcosB - cosAsinB
So, sin(270-3θ) = sin270cos(3θ) - cos270sin(3θ)
= (-1)cos(3θ) - (0)sin(3θ) = -cos(3θ)
Fareed A.
asked 11/28/18Let
θ=54
5θ=270
2θ+3θ=270
2θ=270-3θ
sin(2θ)=sin(270-3θ)
sin(2θ)= -cos(3θ)
From where does - ve sign come from?
.
270-3θ will be in 2quad where sin is +ve.
sin(A-B) = sinAcosB - cosAsinB
So, sin(270-3θ) = sin270cos(3θ) - cos270sin(3θ)
= (-1)cos(3θ) - (0)sin(3θ) = -cos(3θ)
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