A goldsmith mixed 20 g of a 60% gold alloy with 80 g of a 20% gold alloy. What is the percent concentration of the resulting alloy?

Question

I need all the work for this problem please.

Answer 1

20 g of an alloy that is 60% gold = 20 g x 0.60 = 12 g of gold

80 g of an alloy that is 20% gold = 80 g x 0.20 = 16 g of gold

Total amount of gold = 12 g + 16 g = 28 g of gold

Total amount of material = 20 g + 80 g = 100 g

Percent concentration of the resulting alloy = 28 g/100 g (x100%) = 28%