
Mark M. answered 11/25/18
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Mathematics Teacher - NCLB Highly Qualified
(4k)2 - 4(k)(3) < 0
16k2 - 12k < 0
2k(8k - 6) < 0
Either
k > 0 and 8k - 6 < 0 implying k < 3/4
Or
k < 0 and 8k - 6 > 0 implying k > 3/4, not possible since k < 0.
Thus 0 < k < 3/4 results in non-real roots.