y = Aekt
7 = Ae-3k and 1 = Aek
A = e-k
7 = e-ke-3k = e-4k
k =(-1/4) ln 7
You can look up the ln and then solve for A
Daniel L.
asked 11/20/18Find the formula for an exponential function that passes through the two points given.
(−3,7) and (1,1)
y = Aekt
7 = Ae-3k and 1 = Aek
A = e-k
7 = e-ke-3k = e-4k
k =(-1/4) ln 7
You can look up the ln and then solve for A
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