y = a·bx
Plug in (0,7):
7 = a·b0
7 = a·1
7 = a
y = 7·bx
Plug in (4,16807)
16807 = 7·b4
2401 = b4
7 = b
y = 7·7x = 7x+1
Daniel L.
asked 11/20/18Find the formula for an exponential function that passes through the two points given.(0,7) and (4,16807).
y = a·bx
Plug in (0,7):
7 = a·b0
7 = a·1
7 = a
y = 7·bx
Plug in (4,16807)
16807 = 7·b4
2401 = b4
7 = b
y = 7·7x = 7x+1
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