if g(-5)=2, g'(-5)=-2, f(-5)=-3, and f'(-5)=-1, what is the value of h'(-5) where h(x)= f(x)g(x)? show your work

Answer 1

Hi Dieris,

This is how text book writers and math teachers see if you understand the PRODUCT RULE.

h(x)=f(x)g(x), then h'(x) = f(x) g'(x) + g(x) f'(x)

Now just plug in all of the values with x=-5

h'(-5) = f(-5) g'(-5) + g(-5) f'(-5) = (-3)(-2) + (2)(-1)

h'(-5) = 6-2 = 4