
Philip P. answered 11/11/18
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Effective and Patient Math Tutor
y = kx + 1
M = (x,y) = (1,3)
y = kx + 1
3 = k(1) + 1
Solve for k.
James L.
asked 11/11/18Philip P. answered 11/11/18
Effective and Patient Math Tutor
y = kx + 1
M = (x,y) = (1,3)
y = kx + 1
3 = k(1) + 1
Solve for k.
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