Arthur D. answered 11/10/18
Mathematics Tutor With a Master's Degree In Mathematics
4x^2-27x+18=0
4*18=2*2*2*3*3=(2*2*2*3)*3 =24*3 and 24+3=27
(4x )(x ) so far
(4x 3)(x 6) so far
(4x-3)(x-6)=0
4x-3=0
4x=3
x=3/4
x-6=0
x=6
Meghan B.
asked 11/10/18I have 4x2-27x+18=0
While I know you usually begin by finding a factor of all three numbers, there is not one for these numbers. How would I continue?
Arthur D. answered 11/10/18
Mathematics Tutor With a Master's Degree In Mathematics
4x^2-27x+18=0
4*18=2*2*2*3*3=(2*2*2*3)*3 =24*3 and 24+3=27
(4x )(x ) so far
(4x 3)(x 6) so far
(4x-3)(x-6)=0
4x-3=0
4x=3
x=3/4
x-6=0
x=6
Lauren H. answered 11/10/18
Experienced High School Chemistry Teacher
4x2-27x+18=0
(4x - 3)(x - 6) = 0
how I did it:
I tested the possible factors of 18, realizing that for the b term to be negative and the c term to be positive, the factors of 18 would both be negative. I used -3 and -6. Then, I saw that 4 x -6 = -24, and, -24 + -3 = 27.
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