If the width of a rectangular field is 3 metres more than one-half of its length and its perimeter is 48 metres, then the dimensions are

Question

If the width of a rectangular field is 3 metres more than one-half of its length and its perimeter is 48 metres, then the dimensions are

Answer 1

Let's first identify what's given and remember that perimeter is the sum of all sides and rectangles have two equal sides:

w = 3 + 1/2l

p = 2l + 2w = 48

We can solve for the length of the sides using substitution:

2l + 2w = 48

2l + 2 (3+1/2l) = 48

2l+6+l=48

3l+6=48

3l=42

l=14

Now we can also find w

w=3+1/2l=3+1/2(14)=3+7=10

The dimensions are 10 x 14 meters.