Two bodies of masses m1 and m2 are dropped from heights h1 and h2. If they have equal momenta on reaching ground and h1>h2. Will the ratio of kinetic energy of m1 to that of m2 is greater than 1

Answer 1

K1 = p1^2 / (2m1)

K2 = p2^2 / (2m2)

p1 = p2 = p

K1/K2 = [p^2 / (2m1)] / [p^2 / (2m2)] = m2/m1

If m1 > m2, then K1/K2 < 1

If m1 = m2, then K1/K2 = 1

If m1 < m2, then K1/K2 > 1