A transformer has a primary voltage of 549 V and a primary current of 121.66 A. The ratio of primary to secondary loops is 440. What is the current in the secondary?

Question

(show units: type V for Volts, A for amps, ohms for Ω , W for Watts, eV for electron volts, Hz for Hertz, N for newtons,  m for meters, s for seconds, J for Joules, cal for calories, m/s for meters per second  etc.)

Answer 1

Primary Current Divided By Secondary Current Equals Secondary Loops Divided By Primary Loops.

Abbreviate to I_p/I_s = N_s/N_p and enumerate as 121.66 Ampères ÷ I_s = 1loop ÷ 440 loops which gives I_s as

53530.4 Ampères.