The density of a swimming pool is 1000 kg m cubed. The depth of the pool is 3 metres. Calculate the pressure exerted at the bottom of the water.

Answer 1

Pa = atmospheric pressure (look it up in units of N/m^2)

D = density of water (given as 1000 kg/m^3)

h = depth of water = 3m

g = acceleration of gravity = 9.8 m/s^2

At a depth of h (meters), the static pressure is

P(h) = Pa + Dgh

Plug in the numbers and get P(h) in units of N/m^2.