atm,temp,volume

Question

A balloon with a volume of 5.58 L is at a pressure of 0.86 atm and a temperature of 12^oC. If the pressure is increased to 4.2 atm and the temperature is raised to 48^oC, what is the new volume of the balloon?

Answer 1

Hello Katrina

To answer this question, you will need to use the combined gas law equation.

P1V1 / T1 = P2V2 / T2

P1 = 0.86 atm

V1 = 5.56 L

T1 = 12 °C + 273K = 285 K

P2 = 4.2 atm

V2 = ?

T2 = 48 °C + 273K = 321 K

Rearrange the above equation to solve for V2.

V2 = P1V1T2 / P2T1

= (0.86 x 5.56 x 321) / (4.2 x 285)

= 1.28 L