Solve the following equations

Question

(a) x − 2 = 3 x

(b) (1−x)(1+x)= 1 2

(c) 120e−4x = e2x (d) 3−ln(x+5) = 0

Answer 1

a) x =-1

b) 1 -x^2 = 12

x^2 = -11

x = + or - isqr11

c) 120e^-4x = e^2x

120 = e^6x

6x = ln120

x = (1/6)ln120

d) 3 -ln(x+5) = 0

ln(x+5) = 3

x +5 = e^3

x= e^3 - 5