Raymond B. answered 06/23/25
Math, microeconomics or criminal justice
cost
= 20+23+26+29+ .. a30
where each term is 3 more than previous term
an AP with d=3, a1=20
an =a1 +d(n-1) = 20 +3(n-1) = 3n+17
a30 = 3(29)+17 = 87+17=$104 for 30th meter
sn = n(a1+an)/2 = 30(20+104)/2 = 15(124) =$1995 = cost of 30 meter hole
with only $1,000 budget the most that can be dug is 20 meters
20+23 + ... +74+ 77 = $970. another meter costs over budget
an=77
sn=(n/2)(20+77)= (97n)/2=48.5n </=1,000
n =/< 1000/48.5=about 20.6
20th term/meter
20 meters maximum on $1,000 budget