find three consecutive integers such that the sum of the first and the second is 60 more than the third

Answer 1

X is the first of 3 consecutive integers

X+1 is the 2nd of 3 consecutive integers

X+2 is the 3rd of 3 consecutive integers

The some of the first and second is 60 more than the third

x + x+1 = 60 + x+2

2x + 1 = x + 62

2x = x+ 61

x = 61

61 , 62, and 63