Alright, Nikki, let's do this thing.
Let's let the speed = s.
Then, the rate with the wind is s + 25 and against the wind is s - 25.
We know that distance = rate x time, so time = distance/rate.
We have, then, 440/(s+25) = 340/(s-25) since the times are the SAME.
Cross multiply and get 440(s-25) = 340(s+25).
Can you solve from here?