x^2+(2x+6)^2=(2x+4)^2

so since you have (2x+4)^2 and (2x+6)^2. Your first job is to take this solve and uncoil these two expressions first.

(2x+4)^2 can be solved using the squared for formula.

(a+b)^2 = (a^2 + 2*a*b + b^2) = (a+b) * (a+b)

Therefore (2x+4)^2 = (2x)^2 + 2*2x*4 + (4)^2

= 4x^2 + 16x + 16

and Therefore (2x+6)^2 = (2x)^2 + 2*2x*6 + (6)^2

= 4x^2 + 24x + 36

Now that those polynomials are taken cared we have to put all together in the solution:

x^2 + 4x^2 + 24x + 36 = 4x^2 + 16x + 16.

Its better to put everything to one side and make it equal to zero.

so, x^2 + 4x^2 + 24x + 36 - (4x^2 +16x +16) = 4x^2 + 16x + 16 - ( 4x^2 + 16x + 16)

x^2 + 4x^2 + 24x + 36 - 4x^2 -16x -16 = 0

group the x^2 with each other and add them and do the same for the x's and the numbers.

so, x^2 + 4X^2 - 4x^2 + 24x - 16x + 36 -16 = 0

then you have, x^2 + 8x + 20 = 0

Now solve this equation using factorization or the quadratic equation.

reply to this comment if you need further help.

## Comments

Am I going to get an answer?

This is a Pythagorean Quadratic....

Any help would be appreciated.

Dear Eric,

Next time, please, copy the problem exactly as it appear in the original source, and not your own interpretation.

2x+6 > 2x+4 , so the equation you gave us to solve does not match the description you wrote.

I gave the precise equation - x^2+(2x+6)^2=(2x+4)^2

This is to be factored, it also requires the use of the Pythagorean Theorem to solve it....

If it was relayed any differently, I don't recall my mistake...

Ahmed has half of a treasure map,

which indicates that the treasure is buried in the

desert 2x 6 paces from Castle Rock. Vanessa has the

other half of the map. Her half indicates that to find

the treasure, one must get to Castle Rock, walk x paces to the north, and then walk 2x 4 paces to the east. If they

share their information, then they can find x and save a lot of digging. What is x? This is the exact question.

Thanks